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      Introduction to climate dynamics and climate modelling - The carbonate compensation
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            <h2>
              4.3.1 The carbonate compensation
            </h2>
            <p>
              As discussed in section <a href="chapter2_node14.xml">2.3.4</a>, the <i>CaCO</i><sub>3</sub> burial in sediments
              is ultimately compensated for by the input from rivers. Because <a name="weathering" href="glossary_w.html#weathering">weathering</a> and
              <a name="sedimentation" href="glossary_s.xml#sedimentation"> sedimentation</a> 
              rates appear relatively independent, there is no a priori reason why
              these two processes should be in perfect balance at any particular
              time. However, any imbalance between them can lead to large variations of the stock
              of calcium carbonate in the ocean (and
              thus of the <a name="alkalinity" href="glossary_a.html#alkalinity">alkalinity</a>, 
              Eq. <a href="chapter2_node12_1.xml#GrindEQ__2_45_">2.45</a>) on millennial to multi-millennial <a href="glossary_t.html#timescale">timescales</a> . 
              This would imply significant changes in the
              oceanic <i>pCO</i><sub>2</sub> (section <a href="chapter2_node12.xml">2.3.2</a>) and in the atmospheric
              <i>CO</i><sub>2</sub> concentration. Such large shifts were not observed, at least
              over the last tens of million years, because of a stabilising feedback between the
              oceanic carbon cycle and the underlying sediment referred to as <a name="carbonate_compensation" href="glossary_c.xml#carbonate_compensation">carbonate
              compensation</a>.
            </p>
            <p>
              To understand this feedback, it is necessary to analyse the mechanisms
              controlling the dissolution of <i>CaCO</i><sub>3</sub>. First, let's define the solubility
              
               <i>K</i><sup>CaCO<sub>3</sub></sup> (similarly to the solubility of <i>CO</i><sub>2</sub> in Eq. <a href="chapter2_node12_1.xml#GrindEQ__2_43_">2.43</a>) from the 
               equilibrium
              relationship for the dissolution of <i>CaCO</i><sub>3</sub> (Eq. <a href="chapter2_node12_2.xml#GrindEQ__2_47_">2.47</a>).
            </p>
            <div class="c1">
              <a name="GrindEQ__4_14_" id="GrindEQ__4_14_"></a><!-- MATH
 \begin{equation}
K^{CaCo_{3} } =\left[CO_{3}^{2-} \right]_{sat} \left[Ca_{}^{2+} \right]_{sat}
\end{equation}
 -->
              <table class="equation" cellpadding="0" width="90%" align="center">
                <tr valign="middle">
                  <td nowrap="nowrap" align="center">
                    <math xmlns="http://www.w3.org/1998/Math/MathML" display="block" 
                    overflow="scroll"><msup><mi>K</mi><mrow><mrow><mi>C</mi><mi>a</mi><mi>C</mi>
                    </mrow><msub><mi>o</mi><mn>3</mn></msub></mrow></msup><mo>=</mo><msub><mfenced 
                    close="]" open="[" separators=""><mi>C</mi><msubsup><mi>O</mi><mn>3</mn><mrow>
                    <mn>2</mn><mo>-</mo></mrow></msubsup></mfenced><mrow><mi>s</mi><mi>a</mi><mi>
                    t</mi></mrow></msub><msub><mfenced close="]" open="[" separators=""><mi>C</mi>
                    <msubsup><mi>a</mi><mrow/><mrow><mn>2</mn><mo>+</mo></mrow></msubsup></mfenced>
                    <mrow><mi>s</mi><mi>a</mi><mi>t</mi></mrow></msub><mspace linebreak="newline"/>
                    </math>
                  </td>
                  <td nowrap="nowrap" width="10" align="right">
                    (4.17)
                  </td>
                </tr>
              </table>
            </div><br clear="all" />
            <p>
              where [<i>CO</i><sub>3</sub><sup>2-</sup>]<sub><i>sat</i></sub> and [<i>Ca</i><sup>2+</sup>]<sub><i>sat</i></sub> are the concentrations when the equilibrium
              between <i>CaCO</i><sub>3</sub> and the dissolved ions is achieved, i.e at
              saturation. If at one location in the ocean the product [<i>CO</i><sub>3</sub><sup>2-</sup>][<i>Ca</i><sup>2+</sup>]
              is higher than 
               <i>K</i><sup>CaCO<sub>3</sub></sup>, the water is said to be supersaturated with respect
              to <i>CaCO</i><sub>3</sub>. If the product is smaller than 
               <i>K</i><sup>CaCO<sub>3</sub></sup>, the water is undersaturated. As the
              variations of the concentration in <i>Ca</i><sup>2+</sup> are much smaller than the variations in the concentration of 
               <i>CO</i><sub>3</sub><sup>2-</sup>, saturation is mainly influenced by [<i>CO</i><sub>3</sub><sup>2-</sup>].
            </p>
            <p>
              Observations show that the concentration of <!-- MATH
 $CO_{3}^{2-}$
 -->
               <i>CO</i><sub>3</sub><sup>2-</sup> decreases with depth (inset of Fig. <a href=
              "#image4x07">4.13</a>). The downward transport of inorganic carbon by the <a name="soft_tissue_pump" href="glossary_s.xml#soft_tissue_pump">soft tissue pump</a>
              and the <a name="carbonate_pump" href="glossary_c.xml#carbonate_pump">carbonate pump</a> might suggest the opposite. However, we must recall that the alkalinity is mainly
              influenced by the concentration of bicarbonate and carbonate ions (see the discussion
              of Eq. <a href="chapter2_node12_1.xml#GrindEQ__2_45_">2.45</a>). Neglecting the small contribution of carbonic acid, <i>Alk</i> can be
              approximated by:
            </p>
            <div class="c1">
              <a name="GrindEQ__4_15_" id="GrindEQ__4_15_"></a><!-- MATH
 \begin{equation}
Alk\simeq \left[HCO_{3}^{-} \right]+2\left[CO_{3}^{2-} \right]
\end{equation}
 -->
              <table class="equation" cellpadding="0" width="90%" align="center">
                <tr valign="middle">
                  <td nowrap="nowrap" align="center">
                    <math xmlns="http://www.w3.org/1998/Math/MathML" display="block" 
                    overflow="scroll"><mrow><mi>A</mi><mi>l</mi><mi>k</mi></mrow><mo>&#x2243;</mo>
                    <mfenced close="]" open="[" separators=""><mrow><mi>H</mi><mi>C</mi></mrow>
                    <msubsup><mi>O</mi><mn>3</mn><mo>-</mo></msubsup></mfenced><mo>+</mo><mn>2</mn>
                    <mfenced close="]" open="[" separators=""><mi>C</mi><msubsup><mi>O</mi><mn>
                    3</mn><mrow><mn>2</mn><mo>-</mo></mrow></msubsup></mfenced><mspace 
                    linebreak="newline"/></math>
                  </td>
                  <td nowrap="nowrap" width="10" align="right">
                    (4.18)
                  </td>
                </tr>
              </table>
            </div><br clear="all" />
            <p>
              If we also neglect the influence of the carbonic acid on the <a name="dissolved_inorganic_carbon" href="glossary_d.html#dissolved_inorganic_carbon"><i>DIC</i></a>, we can
              write:
            </p>
            <div class="c1">
              <a name="GrindEQ__4_16_" id="GrindEQ__4_16_"></a><!-- MATH
 \begin{equation}
DIC\simeq \left[HCO_{3}^{-} \right]+\left[CO_{3}^{2-} \right]
\end{equation}
 -->
              <table class="equation" cellpadding="0" width="90%" align="center">
                <tr valign="middle">
                  <td nowrap="nowrap" align="center">
                    <math xmlns="http://www.w3.org/1998/Math/MathML" display="block" 
                    overflow="scroll"><mrow><mi>D</mi><mi>I</mi><mi>C</mi></mrow><mo>&#x2243;</mo>
                    <mfenced close="]" open="[" separators=""><mrow><mi>H</mi><mi>C</mi></mrow>
                    <msubsup><mi>O</mi><mn>3</mn><mo>-</mo></msubsup></mfenced><mo>+</mo><mfenced 
                    close="]" open="[" separators=""><mi>C</mi><msubsup><mi>O</mi><mn>3</mn><mrow>
                    <mn>2</mn><mo>-</mo></mrow></msubsup></mfenced><mspace linebreak="newline"/>
                    </math>
                  </td>
                  <td nowrap="nowrap" width="10" align="right">
                    (4.19)
                  </td>
                </tr>
              </table>
            </div><br clear="all" />
            <p>
              This leads to
            </p>
            <div class="c1">
              <a name="GrindEQ__4_17_" id="GrindEQ__4_17_"></a><!-- MATH
 \begin{equation}
\left[CO_{3}^{2-} \right]\simeq Alk-DIC
\end{equation}
 -->
              <table class="equation" cellpadding="0" width="90%" align="center">
                <tr valign="middle">
                  <td nowrap="nowrap" align="center">
                    <math xmlns="http://www.w3.org/1998/Math/MathML" display="block" 
                    overflow="scroll"><mfenced close="]" open="[" separators=""><mi>C</mi><msubsup>
                    <mi>O</mi><mn>3</mn><mrow><mn>2</mn><mo>-</mo></mrow></msubsup></mfenced><mo>
                    &#x2243;</mo><mrow><mi>A</mi><mi>l</mi><mi>k</mi></mrow><mo>-</mo><mrow><mi>
                    D</mi><mi>I</mi><mi>C</mi></mrow><mspace linebreak="newline"/></math>
                  </td>
                  <td nowrap="nowrap" width="10" align="right">
                    (4.20)
                  </td>
                </tr>
              </table>
            </div><br clear="all" />
            <p>
              The dissolution of calcium carbonate releases 
               <i>CO</i><sub>3</sub><sup>2-</sup> directly. This is consistent with Eq. <a href=
              "#GrindEQ__4_17_">4.20</a> as the dissolution of 1 mole
              of <i>CaCO</i><sub>3</sub> increases <i>Alk</i> by 2 and <i>DIC</i> by 1. By
              contrast, the remineralisation of organic matter mainly affects the DIC, producing a
              decrease in 
               [<i>CO</i><sub>3</sub><sup>2-</sup>], according to Eq. <a href=
              "#GrindEQ__4_17_">4.20</a>. In the present oceanic conditions, the
              influence of the <a href="glossary_s.xml#soft_tissue_pump">soft tissue pump</a> appears to dominate, leading to the observed
              decrease of 
               <i>CO</i><sub>3</sub><sup>2-</sup> at depth. As the solubility of
              <i>CaCO</i><sub>3</sub> increases in the deep ocean, mainly because of its pressure
              dependence, the upper ocean tends to be supersaturated while the deep ocean is
              undersaturated. The depth at which those two regions are separated is called the
              <a name="saturation_horizon" href="glossary_s.xml#saturation_horizon">saturation 
              horizon</a> (inset of Fig. <a href="#image4x07">4.13</a>).
            </p>
            <p>
              Some of the <i>CaCO</i><sub>3</sub> that leaves the surface layer is dissolved
              in the ocean water column, but a significant part is transferred to the sediment.
              There, a fraction of the <i>CaCO</i><sub>3</sub> is dissolved and reinjected into
              the ocean, the rest being buried in the sediment on a long timescale. In order
              to describe those processes, the <a name="lysocline" href="glossary_l.xml#lysocline">lysocline</a> is defined as the depth up to which
              <i>CaCO</i><sub>3</sub> in sediments is subject to very little dissolution while below the
              <a name="calcite_compensation_depth" href="glossary_c.xml#calcite_compensation_depth">Calcite Compensation Depth</a> (CCD) 
              nearly all the calcite is lost from present in the sediment is lost by dissolution. 
              The CCD is then the depth at which the input from
              sedimentation exactly balances the loss from dissolving calcite at the top of the sediment. The
              region between the <a href="glossary_l.xml#lysocline">lysocline</a> and the CCD is called the transition zone (Fig. <a href=
              "#image4x07">4.13</a>).
            </p>
            <p>
              The position of the transition zone depends on several factors, in particular the presence 
              of organic material in the sediment. It is significantly influenced by the saturation of 
              the waters above the sediment: if they are undersaturated, dissolution in the sediment tends 
              to be relatively high, but if the waters are supersaturated dissolution is very low (as in the upper ocean).  
              If the <a href="glossary_s.xml#saturation_horizon">saturation horizon</a>
              changes, the position of the transition zone is modified and the regions of the
              ocean where <i>CaCO</i><sub>3</sub> is preserved in sediment change.
            </p>
            <div align="center">
              <a name="image4x07" id="image4x07"></a><a name="3392"></a>
              <table>
                <caption align="bottom"><p align="center">
                  <strong>Figure 4.13:</strong> a) The current 
                  <i>CaCO</i><sub>3</sub> budget in PgC yr<sup>-1</sup>. 0.13 PgC yr<sup>-1</sup>
                  comes from the rivers and about 1.0 PgC yr<sup>-1</sup> of <i>CaCO</i><sub>3</sub>
                  is produced in the ocean of which 0.5 PgC yr<sup>-1</sup> is dissolved in
                  the water column and 0.5 PgC yr<sup>-1</sup> is transferred to the sediment.
                  Of the <i>CaCO</i><sub>3</sub> transferred to the sediment,
                  0.37 PgC yr<sup>-1</sup> is dissolved and goes back to the deep ocean, and
                  0.13 PgC yr<sup>-1</sup> accumulates in the sediment, so balancing the input from rivers. 
                  b) If the river input doubles, the saturation horizon deepens, so that less <i>CaCO</i><sub>3</sub> 
                  dissolves and more accumulates in the sediment a new balance is reached. 
                  Insets show  the vertical profiles of [<i>CO</i><sub>3</sub><sup>2-</sup>], solubility and the saturation
                  horizon. Figure from <a class="ref" href="chapter4_node14.html">Sarmiento and Gruber (2006)</a>. Reprinted by permission of Princeton University Press.
                </p></caption>
                <tr>
                  <td>
                    <div>
                      <img  align="bottom" border="0" src=
                      "./images/image4x07.jpg" alt="Image image4x07" />
                    </div>
                  </td>
                </tr>
              </table>
            </div>
            <p>
              Those shifts in the <a href="glossary_s.xml#saturation_horizon">saturation horizon</a> are responsible for the stabilisation of the
              ocean alkalinity. Imagine for instance that the input of <i>CaCO</i><sub>3</sub> from
              the rivers doubles because of more intense weathering on continents (Fig. <a href=
              "#image4x07">4.13</a>). The alkalinity of the ocean
              will increase. As a consequence the [<i>CO</i><sub>3</sub><sup>2-</sup>] will increase (Eq. <a href=
              "#GrindEQ__4_17_">4.20</a>) and
              the saturation horizon will fall. The fraction of the ocean floor which is in contact
              with undersaturated waters will increase. This would lead to a higher accumulation of
              <i>CaCO</i><sub>3</sub> in sediment and thus a larger net flux of
              <i>CaCO</i><sub>3</sub> from the ocean to the sediment. This fall in the
              <a href="glossary_s.xml#saturation_horizon">saturation horizon</a> will continue until a new balance 
              is achieved between the
              increased input of  <i>CaCO</i><sub>3</sub> from the rivers and the greater accumulation in the sediments.
            </p>
            <p>
              This feedback strongly limits the amplitude of the variations in alkalinity in the
              ocean and thus of the atmospheric <i>CO</i><sub>2</sub> concentration. For instance,
              it has been estimated that, in the example presented above, a doubling of the river
              input of <i>CaCO</i><sub>3</sub> would only lead to a change of the order of 30 ppm
              in the concentration of atmospheric <i>CO</i><sub>2</sub>.
            </p>
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